![]() Then we would expect to have electronic states with the symmetries $ \Sigma^ , \Sigma^-$ and $ \Delta $īut this does not address the issue of whether the states are singlet or triplet - I think the key thing is that two electrons / or hole and electron / are in different orbitals so that singlet and triplet electronic states with these symmetries can be made. Which means that if a molecule has two electrons in two different $\pi$ orbitals. It suggests that multiplication of $\Pi \times \Pi$ symmetry gives Looking at 'Tables for Group Theory' (Atkins, Child and Phillips, OUP 1970) molecular hydrogen did not have any states of this symmetry when I looked it up. It may be necessary to have thee partially filled orbitals. Sigma symbol decimal Sigma symbol hex
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